Reverse Integer | LeetCode 7 | Math Explained in C++

🚀 LeetCode Problem 7: Reverse Integer | C++ Solution Explained

In this video, we solve LeetCode Problem 7 — Reverse Integer using C++ with a simple Math approach.

📌 Topics Covered:
✔️ Problem Explanation
✔️ Digit Extraction
✔️ Modulo Operator
✔️ Overflow Handling
✔️ Live Coding in C++
✔️ Time Complexity
✔️ Space Complexity

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🧠 Problem Statement

Given a signed 32-bit integer x,

return x with its digits reversed.

If reversing x causes the value to go outside the signed 32-bit integer range, return 0.

Example:

Input:

x = 123

Output:

321

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⚡ Approach

1️⃣ Extract last digit using modulo

2️⃣ Build reversed number

3️⃣ Remove last digit from original number

4️⃣ Repeat until number becomes zero

5️⃣ Check overflow and return answer

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⏱️ Time Complexity

O(d)

where d is the number of digits.

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💾 Space Complexity

O(1)

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🔗 Problem Link

https://leetcode.com/problems/reverse-integer/

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🌐 Connect With Me

💻 GitHub:
https://github.com/Jilanmansuri

💼 LinkedIn:
https://linkedin.com/in/jilan-mansuri-235b38392/

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Thank you for watching ❤️

#leetcode
#leetcode7
#reverseinteger
#math
#cpp
#cplusplus
#coding
#dsa
#programming
#leetcodeeasy

Видео Reverse Integer | LeetCode 7 | Math Explained in C++ канала Jilan DEV