Palindrome Number | LeetCode 9 | C++ Explained

🚀 LeetCode Problem 9: Palindrome Number | C++ Solution Explained

In this video, we solve LeetCode Problem 9 — Palindrome Number using C++ with a complete step-by-step explanation.

📌 Topics Covered:
✔️ Problem Explanation
✔️ Understanding Palindrome Numbers
✔️ Approach & Logic
✔️ Step-by-Step Dry Run
✔️ Live Coding in C++
✔️ Time Complexity
✔️ Space Complexity

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🧠 Problem Statement

Given an integer x, return true if x is a palindrome, and false otherwise.

A palindrome number remains the same after reversing it.

Examples:
121 → true
1331 → true
10 → false

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⚡ Approach

1️⃣ Store the original number

2️⃣ Extract the last digit using modulo 10

3️⃣ Build the reversed number digit by digit

4️⃣ Remove the last digit using divide by 10

5️⃣ Repeat until the number becomes 0

6️⃣ Compare original and reversed number

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⏱️ Time Complexity

O(log n)

We process each digit exactly one time.

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💾 Space Complexity

O(1)

Only a few variables are used.

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🔗 Problem Link

https://leetcode.com/problems/palindrome-number/

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🌐 Connect With Me

💻 GitHub:
https://github.com/Jilanmansuri

💼 LinkedIn:
https://linkedin.com/in/jilan-mansuri-235b38392/

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Видео Palindrome Number | LeetCode 9 | C++ Explained канала CodeByJilan