Finding Students with Second Lowest Grade – Detailed Version #Python #HackerRank #NestedLists

In this video, we solve the HackerRank problem of finding the student(s) with the second lowest grade in a class using Python. We store student names and grades in a nested list, identify the second lowest grade, and then print the names of all students having that grade in alphabetical order.

Step-by-Step Explanation:

Input Reading:

Read the number of students.

For each student, read the name and grade and store them as a nested list.

#InputHandling #NestedLists

Identify Unique Grades:

Create a sorted list of unique grades to easily determine the second lowest grade.

#Sorting #UniqueValues

Filter Students:

Extract the names of students whose grade matches the second lowest grade.

Sort these names alphabetically.

#Filtering #Sorting

Output:

Print each name on a new line.

#Output #Result

Copy and paste the code below into your Jupyter Notebook to practice the detailed solution!

Code for Detailed Version (Copy-Paste in Jupyter Notebook):

def find_second_lowest_students():
# Read the number of students
n = int(input().strip())
students = []

# Collect student names and grades
for _ in range(n):
name = input().strip()
grade = float(input().strip())
students.append([name, grade])

# Extract a sorted list of unique grades
unique_grades = sorted({grade for name, grade in students})

# The second lowest grade
second_lowest = unique_grades[1]

# Get names of all students with the second lowest grade and sort them alphabetically
second_lowest_students = sorted([name for name, grade in students if grade == second_lowest])

# Print the names of the students
for student in second_lowest_students:
print(student)

if __name__ == '__main__':
find_second_lowest_students()

Видео Finding Students with Second Lowest Grade – Detailed Version #Python #HackerRank #NestedLists канала CodeVisium