The maximum value off(x)=|■(sin^2x&1+cos^2x&cos2x@1+sin^2x&cos^2x&cos2x@sin^2x&cos^2x&sin2x
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The maximum value of
f(x)=|■(sin^2x&1+cos^2x&cos2x@1+sin^2x&cos^2x&cos2x@sin^2x&cos^2x&sin2x )|,x∈R is,
(a) √5 (b) 5 (c) √7 (d) 3/4
Ans: a
Sol.
C_1+C_2→C_1
|■(2&1+cos^2x&cos2x@2&cos^2x&cos2x@1&cos^2x&sin2x )|
R_1-R_2→R_1
|■(0&1&0@2&cos^2x&cos2x@1&cos^2x&cos2x )|
Open w.r.t. R_1
-(2 sin〖2x-cos2x 〗 )
cos〖2x-2 sin2x 〗=f(x)
├ f(x)┤|_max=√(1+4)=√5
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Видео The maximum value off(x)=|■(sin^2x&1+cos^2x&cos2x@1+sin^2x&cos^2x&cos2x@sin^2x&cos^2x&sin2x канала Math Master - Impetus Gurukul
The maximum value of
f(x)=|■(sin^2x&1+cos^2x&cos2x@1+sin^2x&cos^2x&cos2x@sin^2x&cos^2x&sin2x )|,x∈R is,
(a) √5 (b) 5 (c) √7 (d) 3/4
Ans: a
Sol.
C_1+C_2→C_1
|■(2&1+cos^2x&cos2x@2&cos^2x&cos2x@1&cos^2x&sin2x )|
R_1-R_2→R_1
|■(0&1&0@2&cos^2x&cos2x@1&cos^2x&cos2x )|
Open w.r.t. R_1
-(2 sin〖2x-cos2x 〗 )
cos〖2x-2 sin2x 〗=f(x)
├ f(x)┤|_max=√(1+4)=√5
Downloads our APP for FREE Study Material ,Video Class ,Test paper & Mock test etc...
Click to Download Impetus Gurukul Free Learning App here
https://play.google.com/store/apps/details?id=com.impetusgurukul
To buy complete Course please Visit–
https://www.impetusgurukul.com or contact on 7047832474
join Impetus Gurukul live classes via the official Website:
https://live.impetusgurukul.com
Our Social links
Telegram: https://t.me/impetusgurukul
Facebook: https://www.facebook.com/impetusgurukul
LinkedIn: https://www.linkedin.com/in/dr-sharad...
twitter: https://twitter.com/ImpetusSharad
Видео The maximum value off(x)=|■(sin^2x&1+cos^2x&cos2x@1+sin^2x&cos^2x&cos2x@sin^2x&cos^2x&sin2x канала Math Master - Impetus Gurukul
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18 сентября 2024 г. 21:20:45
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