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DFS Tree 5 | Tourist Reform (CF - 2300) | Graph Theory

In Phase 2 of the 𝐃𝐅𝐒 𝐌𝐚𝐬𝐭𝐞𝐫𝐜𝐥𝐚𝐬𝐬, we mathematically proved that if an undirected graph has no bridges, we can safely route its edges to make it strongly connected.⁣

But what happens when the graph does have bridges?⁣

Welcome to Phase 3: Component Condensation. In this lecture, we tackle Codeforces 732F (Tourist Reform). The goal is to direct the edges of a city's road network to maximize the minimum number of reachable cities.⁣

To solve this, we use our dp[u] prefix-sum math to locate every bridge. If we "cut" these bridges, the graph shatters into isolated islands. These islands are called 2-Edge-Connected Components (2-ECC). Because there are no bridges inside these components, we can make each one strongly connected.⁣

By finding the massive "core" component and routing all bridges towards it, the problem collapses into an elegant two-pass DFS.⁣

🔍 𝐖𝐇𝐀𝐓 𝐘𝐎𝐔 𝐖𝐈𝐋𝐋 𝐃𝐈𝐒𝐂𝐎𝐕𝐄𝐑:⁣

• 𝐆𝐫𝐚𝐩𝐡 𝐒𝐡𝐚𝐭𝐭𝐞𝐫𝐢𝐧𝐠: How bridges naturally divide a graph into 2-Edge-Connected Components.⁣

• 𝐓𝐡𝐞 𝐒𝐭𝐚𝐜𝐤 𝐌𝐞𝐭𝐡𝐨𝐝: How to extract the exact vertices of each component on the fly using a simple stack as our DFS unwinds.⁣

• 𝐂𝐨𝐦𝐩𝐨𝐧𝐞𝐧𝐭 𝐂𝐨𝐧𝐝𝐞𝐧𝐬𝐚𝐭𝐢𝐨𝐧: Why directing all bridges towards the largest 2-ECC guarantees the mathematically optimal answer.⁣

• 𝐓𝐡𝐞 𝐓𝐰𝐨-𝐏𝐚𝐬𝐬 𝐃𝐅𝐒: How to build an incredibly clean implementation that finds the components in pass one, and greedily orients every edge in pass two.⁣

𝐏𝐫𝐨𝐛𝐥𝐞𝐦 𝐋𝐢𝐧𝐤:- https://codeforces.com/contest/732/problem/F

👋 𝐖𝐞𝐥𝐜𝐨𝐦𝐞 𝐭𝐨 𝐭𝐡𝐞 𝐜𝐡𝐚𝐧𝐧𝐞𝐥!⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣⁣ ⁣⁣⁣⁣⁣⁣
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