Day 77/90 | Part 2 |⚡Binary Search Trick That Finds K Closest Elements Fast | LeetCode 658 🚀#9

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Master the Find K Closest Elements problem using the powerful binary search on left bound approach.

In this video, we solve LeetCode 658. Find K Closest Elements using the optimized arr[mid] and arr[mid + k] comparison technique. Instead of checking every possible window or sorting by distance, we binary search for the best starting index of a window of size k.

You’ll learn how to think of the answer as a continuous window, why the left boundary can only go up to arr.length - k, and how this condition works:

if (x - arr[mid] greater than arr[mid + k] - x)

This comparison helps us decide whether the best window is more towards the left or the right side of the array.

In this video, we cover:

Brute force intuition
Why the answer is always a sorted window of size k
How binary search finds the left bound
Why we compare arr[mid] with arr[mid + k]
Number line intuition for closest elements
Dry run with examples
Java code explanation
Time and space complexity

This is an important binary search variation where we are not searching for a target directly. Instead, we are searching for the best window position.

Perfect for anyone preparing for coding interviews, LeetCode practice, DSA patterns, and mastering modified binary search problems.

Hashtags:
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CHAPTERS
00:00 - Introduction
00:31 - LeetCode 658 - Approach 3 - Theory
23:32 - LeetCode 658 - Approach 3 - Code
33:10 - Conclusion

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Видео Day 77/90 | Part 2 |⚡Binary Search Trick That Finds K Closest Elements Fast | LeetCode 658 🚀#9 канала CTO Bhaiya