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6 ATOMIC STRUCTURE | Rutherford nuclear model | IIT advance | JEE main | chemistry | class 11

To practice after watching this video, Buy My Digital book from Team Competishun App: https://teamcompetishun.page.link/digitalbook ATOMIC STRUCTURE | Rutherford nuclear model | IIT advance | JEE main | chemistry | class 11 #Admission_Online_Offline_Batch_7410900901 #Competishun ATOMIC STRUCTURE | Rutherford nuclear model | IIT advance | JEE main | chemistry | class 11 iit jee advanced |mains jee This is the sixth lecture of atomic structure by ALK sir .The detailed explanation with complete time stamp is given below: 00:00 - 02:23 Rutherford's Nuclear model : (1) Most of the space of atom is empty because all electronic charge is spread into the large spherical volume of atom. 02:24 - 03:50 (2) All posiitve charge and almost entire mass of an atom is concentrated into nucleus (extremely small size) 03:51 - 05:00 (3) Since elctrons are revolving around the nucleus ,the force of attraction between electron and nucleus is balanced by centrifugal force. 05:51 - 07:00 (4)Size of atom is of the order of 10^-10 metre whereas size of nucleus is of the order of 10^-15 metre 07:01 - 09:50 Determination of size of atom dAl (s)= 2.7 g/ml ,molar mass of Al =27 g/ml .Vmolar =27/27 cm^3 = r=10 ^-8 cm or 10^-10 m 09:51 - 18:00 Determination of approximate size of nuleus : Consider the head on collision between alpha particle and gold nucleus (when alpha is recoiled).Sir has explained it with the help of diagram.Total energy us constant , now find rmin which is the distance of closest approach.Applying law of conservation of energy .Appkying law of consservation of energy .Now we will find r min 18:01 - 26:25 r min is directly proportional to atomic number and inversely proprtional to kinetic energy.Sir has explained it with the help of a graph ( distance between alpha particle and gold nucleus).Sir has further explained about the rmin and other postulates related to it. 26:26 - 28:10 (5) Approximate size of nucleus ,r directly proportional to A^1/3 or r=r0xA^1/3 28:11 - 29:03 (6) Number of alpha particles deflected at an angle theta Ntheta= 1/sin ^gamma(theta/2) This is the sixth lecture by Alk sir .Topics covered in this video by ALK sir: 1. postulates of Rutherford model 2. determination of order of size of atom 3. distance of closest approach This lecture is very important for the science students of class 11 and for the jee aspirants.This lecture covers all the important theory and concepts related to Jee mains and advanced. #alksir #atomicstructureclass11 #iitjee #jeemain #jeeadvanced ATOMIC STRUCTUREALK Sir, Rutherford nuclear modelALK Sir, IIT advanceALK Sir, JEE mainALK Sir, chemistryALK Sir, class 11ALK Sir,

Видео 6 ATOMIC STRUCTURE | Rutherford nuclear model | IIT advance | JEE main | chemistry | class 11 автора Легко понять геометрию
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