834. Sum of Distances in Tree || LeetCode POTD || Explained in HINDI
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In this video, we'll explore an efficient algorithm to calculate the sum of distances in a tree for each node.
Approach:
We'll use Depth First Search (DFS) to traverse the tree and calculate the sum of distances for each node.
We'll maintain two arrays: ans to store the sum of distances for each node, and count to store the count of nodes in the subtree rooted at each node.
First, we'll perform DFS from the root (node 0) to calculate the ans and count arrays.
Then, we'll perform another DFS to update the ans array based on the parent-child relationship. For each node, we'll subtract the count of nodes in its subtree and add the count of nodes in the complement subtree (N - count[child]) to get the sum of distances for the child node.
Finally, we'll return the ans array.
Time Complexity:
The time complexity of the DFS traversal is O(N), where N is the number of nodes in the tree.
Therefore, the overall time complexity of the algorithm is O(N).
Space Complexity:
We're using arrays to store the ans and count values for each node, which requires O(N) space.
Additionally, we're using an adjacency list to represent the graph, which also requires O(N) space.
Therefore, the overall space complexity of the algorithm is O(N).
Whether you're new to problem-solving or seeking insights into Java programming techniques, this video offers valuable insights into tackling similar challenges effectively.
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Видео 834. Sum of Distances in Tree || LeetCode POTD || Explained in HINDI автора Математический Квест: Искатели Трезубца
Видео 834. Sum of Distances in Tree || LeetCode POTD || Explained in HINDI автора Математический Квест: Искатели Трезубца
Информация
11 ноября 2024 г. 8:03:04
00:34:36
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