If the line `y=mx + sqrt(a^2 m^2 - b^2)` touches the hyperbola `x^2/a^2 - y^2/b^2 = 1`

If the line `y=mx + sqrt(a^2 m^2 - b^2)` touches the hyperbola `x^2/a^2 - y^2/b^2 = 1` at the point `(a sec phi, b tan phi)`, show that `phi = sin^(-1) (b/am)`.

Видео If the line `y=mx + sqrt(a^2 m^2 - b^2)` touches the hyperbola `x^2/a^2 - y^2/b^2 = 1` автора Natures Beauty