Coulomb's Law Calculations | Two Charges Separate by a Distance (Pt. 2)

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Note: Coulomb's law is the basic force relationship between two charges. This force acts along the line connecting the charges and is repulsive for like charges and attractive for unlike charges.

F=1/4πϵ⋅(q_1 q_2)/r^2 =(k⋅(q_1 q_2)/r^2 )

Where 1/4πϵ is a constant (k) = (9.0×〖10〗^9 Nm^2/C^2 )

Q1. Two charges q1=3.0×10^(−8) C and q2=−4.0×10^(−8) C are separated by 6.0×10^(−3) m as shown below. What is the force of one on the other?

Q2. The magnitude of the electrostatic force between two small, essentially point-like, charged objects is 5.0×10^(−5) N. Calculate the force for each of the following situations:

a) The distance between the charges is doubled, while the size of the charges stays the same.
b) The charge on one object is tripled, while the charge on the other is halved.
C) Both of the changes in (a) and (b) occur simultaneously.

Q3. What is the magnitude of the force of repulsion between two small spheres 1.0 m apart, if each has a charge of 1.0×10^(−12) C?

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