TANGENT LINE EQUATION - IMPLICIT DIFFERENTIATION - how to find the tangent line at a specific point
In order to find the equation of a tangent line to a given function at a given point, you need to consider what a tangent line is. In order for a line to be considered a tangent line you need to make sure that 2 conditions are met:
1. The line needs to go through the given point.
2. The line needs to have the same slope as the given function at that shared point.
In this video I'll show you how to find the equation of a tangent line to the function y^3+xy-x^2=9 at the point (1, 2). This means that we will be coming up with a linear function that goes through the point that lies on the function at (1, 2) and has the same slope as y^3+xy-x^2=9 at that point. We will come up with this tangent line equation with the derivative of our given function.
READ MORE
+ How to find the equation of a tangent line - https://jakesmathlessons.com/derivatives/how-to-find-the-equation-of-a-tangent-line/
+ Implicit Differentiation - https://jakesmathlessons.com/derivatives/implicit-differentiation/
+ Product Rule - https://jakesmathlessons.com/derivatives/the-product-rule/
+ Chain Rule - https://jakesmathlessons.com/derivatives/the-chain-rule/
WATCH NEXT
+ Tangent line examples - https://www.youtube.com/playlist?list=PL1xaWSV8_rb5ifqcXpKFPl5gv5A6BFooX
+ Implicit Differentiation - https://www.youtube.com/playlist?list=PL1xaWSV8_rb6Q03Kov0f5u61MkF4MxmM4
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+ Download my FREE calc 1 study guide - https://jakesmathlessons.com/Calculus1Course/study-guide-sign-up/
+ My Complete Calculus 1 Package - https://jakesmathlessons.com/complete-calculus-1-package/
+ Work with me! - Come to Wyzant for some 1 on 1 online tutoring with me and get a $40 tutoring credit for FREE - https://is.gd/cqeuOv
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Видео TANGENT LINE EQUATION - IMPLICIT DIFFERENTIATION - how to find the tangent line at a specific point канала Jake's Math Lessons
1. The line needs to go through the given point.
2. The line needs to have the same slope as the given function at that shared point.
In this video I'll show you how to find the equation of a tangent line to the function y^3+xy-x^2=9 at the point (1, 2). This means that we will be coming up with a linear function that goes through the point that lies on the function at (1, 2) and has the same slope as y^3+xy-x^2=9 at that point. We will come up with this tangent line equation with the derivative of our given function.
READ MORE
+ How to find the equation of a tangent line - https://jakesmathlessons.com/derivatives/how-to-find-the-equation-of-a-tangent-line/
+ Implicit Differentiation - https://jakesmathlessons.com/derivatives/implicit-differentiation/
+ Product Rule - https://jakesmathlessons.com/derivatives/the-product-rule/
+ Chain Rule - https://jakesmathlessons.com/derivatives/the-chain-rule/
WATCH NEXT
+ Tangent line examples - https://www.youtube.com/playlist?list=PL1xaWSV8_rb5ifqcXpKFPl5gv5A6BFooX
+ Implicit Differentiation - https://www.youtube.com/playlist?list=PL1xaWSV8_rb6Q03Kov0f5u61MkF4MxmM4
YOU MIGHT ALSO BE INTERESTED IN...
+ Download my FREE calc 1 study guide - https://jakesmathlessons.com/Calculus1Course/study-guide-sign-up/
+ My Complete Calculus 1 Package - https://jakesmathlessons.com/complete-calculus-1-package/
+ Work with me! - Come to Wyzant for some 1 on 1 online tutoring with me and get a $40 tutoring credit for FREE - https://is.gd/cqeuOv
Some links in this description may be affiliate links meaning I would get a small commission for your purchase at no additional cost to you.
Видео TANGENT LINE EQUATION - IMPLICIT DIFFERENTIATION - how to find the tangent line at a specific point канала Jake's Math Lessons
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