JS interview Q87: Logical Operator TRAP! 😵🛑 #javascriptinterview #codinginterviewprep #devshorts

In this short, I’ve explained a classic JavaScript trick question that confuses even experienced developers:

console.log(0 && "Gus" || "Walter");
At first glance, you might expect something different — but the actual output is "Walter".
Let’s break down exactly why this happens 👇

🔹First, JavaScript evaluates the && operator before the || operator — because && has higher precedence.
🔹 So it becomes (0 && "Gus") || "Walter".
🔹 Next, 0 && "Gus" checks the first part — since 0 is falsy, the entire expression becomes 0.
🔹 Now we’re left with 0 || "Walter".
🔹 The || operator returns the first truthy value, and since 0 is falsy, it returns "Walter".

That’s why the final output is "Walter"

In this video, I walk you through each of these steps visually — showing how operator precedence, truthy and falsy values, and short-circuiting work behind the scenes in JavaScript.

Understanding this concept will not only strengthen your JS fundamentals but also help you crack those tricky interview questions with confidence.

If you enjoy learning JavaScript concepts explained simply, don’t forget to like, comment, and subscribe for more such shorts every week! 🚀

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Видео JS interview Q87: Logical Operator TRAP! 😵🛑 #javascriptinterview #codinginterviewprep #devshorts канала Cooking The Code