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How to Compare Values Between Two DataFrames in Python Using Pandas

Learn how to effectively compare the values of a row in one DataFrame with multiple rows from another DataFrame using Python's `Pandas` library. Discover a step-by-step method to calculate the shortest distance and determine location.
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This video is based on the question https://stackoverflow.com/q/65412303/ asked by the user 'soso' ( https://stackoverflow.com/u/14624010/ ) and on the answer https://stackoverflow.com/a/65414031/ provided by the user 'basicknowledge' ( https://stackoverflow.com/u/7182573/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/by-sa/4.0/ ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/by-sa/4.0/ ) license.

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Comparing Values Between DataFrames in Python Using Pandas

When working with data in Python, especially geospatial data, one common challenge is determining the closest match between two sets of coordinates. This guide explores how to compare values from one DataFrame with multiple rows from another DataFrame using Pandas. We will use the Pythagorean theorem to calculate distances between points and ultimately find out the closest location from a reference DataFrame.

Problem Overview

Suppose you have a DataFrame (df) containing variations in longitude and latitude over a certain period, along with another DataFrame (df2) that specifies known locations. You want to compare each point in df to find the nearest location from df2 based on calculated distances.

Here’s a simplified representation of the two DataFrames:

DataFrame df

TimeLongitudeLatitude2020-01-01 01:00100.020.02020-01-01 01:01100.220.12020-01-01 01:02300.130.02020-01-01 01:03200.140.02020-01-01 01:0450.050.0DataFrame df2

LongitudeLatitudeLocation90.020.0District A210.060.0District BApproach to Solve the Problem

To find the nearest location for each point in df, we will:

Calculate the Distance between each point in df and all points in df2 using the Pythagorean theorem.

Identify the Closest Location by selecting the location in df2 that corresponds to the shortest calculated distance.

Store the Results in a new column in df.

Step 1: Setting Up the DataFrames

First, we need to set up the DataFrames in Python using Pandas.

[[See Video to Reveal this Text or Code Snippet]]

Step 2: Calculating the Minimum Distance

To calculate the distance, we can apply a lambda function across each row of df. Here’s how we do it:

[[See Video to Reveal this Text or Code Snippet]]

Explanation of the Lambda Function

The lambda function computes the squared distance between the longitude and latitude of df and df2.

min() is used to find the smallest distance.

The index of the smallest squared distance is used to grab the corresponding location from df2.

Step 3: Viewing the Final Output

After executing the code, the updated df should look like this:

LongitudeLatitudeLocation100.020.0District A100.220.1District A300.130.0District B200.140.0District B50.050.0District AThis output confirms that for each time entry, the corresponding closest district has been correctly identified.

Conclusion

Comparing values across DataFrames in Python using Pandas doesn’t have to be complicated. By efficiently applying a lambda function and utilizing basic geometric principles, we can quickly determine the closest locations to a series of geographic points. This approach can be incredibly useful in various scenarios such as geolocation services, tracking, or any application where distance calculations between coordinates are necessary.

Feel free to adapt the code provided for your specific datasets or use cases!

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