👉 Find the second highest number in a list using the Stream API | Ashok IT #coding #javascript

💡 Java Interview Question:
👉 How do you find the second highest number in a list using the Stream API?

Here’s the modern Java one-liner 👇

int secondHighest = numbers.stream()
.sorted(Comparator.reverseOrder())
.skip(1)
.findFirst()
.orElseThrow(() - new RuntimeException("No second highest found"));
🎯 Explanation:
.sorted(Comparator.reverseOrder()) → sorts the numbers in descending order
.skip(1) → skips the first (highest) element
.findFirst() → picks the next element (second highest)
.orElseThrow() → handles empty list or single-element cases

✅ Clean, readable, and efficient
✅ One of the most asked Stream API interview questions
✅ Shows you understand sorting, streams, and optional handling

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