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How to Convert M to mM in Dilutions (M1V1=M2V2) | BACE Math Practice #13

Problem: Calculate the volume in mL of a 1.5 M NaOH stock solution required to make 275 mL of 50.0 mM NaOH.

In this video, we break down BACE Math Practice Problem #13 step-by-step. If you’re preparing for the Biotechnician Assistant Credentialing Exam (BACE) or any biotechnology lab math, mastering dilutions with unit conversions is critical.

We’ll look at how to handle a mix of Molar (M) and millimolar (mM) concentrations using the standard M1V1 = M2V2 dilution formula and show you exactly how to rearrange it to solve for an unknown volume.

🧪 What You’ll Learn:
How to identify initial (M1) and final (M2) molarity.

The crucial conversion step between M (Molar) and mM (millimolar).

How to rearrange the dilution formula for V1.

Why formatting your answer with one decimal place is critical for your final answer.

📐 The Dilution Equation:
M1V1 = M2V2

📚 More Practice:
If you found this helpful, check out the rest of our BACE Math Practice series to master molarity, unit conversions, and concentration calculations!

#BACE #Biotech #Dilutions #Chemistry #ScienceEducation #STEM #Molarity #M1V1M2V2 #LabMath #UnitConversion

Видео How to Convert M to mM in Dilutions (M1V1=M2V2) | BACE Math Practice #13 канала A Med Talk
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