How to Forcibly Link Dynamic Library to Static Library Global Variables
Learn how to ensure global variables from a static library are linked correctly to a dynamic library in C++.
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This video is based on the question https://stackoverflow.com/q/66977052/ asked by the user 'Narek Jaghinyan' ( https://stackoverflow.com/u/14794536/ ) and on the answer https://stackoverflow.com/a/75736013/ provided by the user 'Narek Jaghinyan' ( https://stackoverflow.com/u/14794536/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.
Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Forcibly link dynamic library to the global variable in the static library
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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/by-sa/4.0/ ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/by-sa/4.0/ ) license.
If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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How to Forcibly Link Dynamic Library to Static Library Global Variables
When working with C++ and building libraries, developers often encounter issues related to the proper linking of static and shared libraries. One common problem is ensuring that global variables defined in static libraries are also recognized in dynamic libraries. This guide will address how to tackle such an issue effectively.
The Problem
Imagine you've created a .c file that has a global string variable and compiled it into a static library. After linking this library to a shared library, you find that the global string symbol is missing. This issue occurs because the variable was not referenced within the dynamic library, leading the linker to discard it.
For example, you may have the following code definitions:
Static Library File
[[See Video to Reveal this Text or Code Snippet]]
Shared Library File
[[See Video to Reveal this Text or Code Snippet]]
You can see that even though you're declaring the external variable in the shared library, it doesn't show up in the .data section of the shared library as intended. The common approach using --whole-archive is not an option here.
The Solution: Making Symbols Visible
To ensure that the global variable from the static library appears in the shared library, you need to use specific techniques to reference it so that the linker keeps it in mind. Here’s a better method to do this:
Step 1: Define the Global Variable
Instead of directly defining a global variable, you can create a function that uses it. This usage guarantees that the linker does not discard the variable as unused.
[[See Video to Reveal this Text or Code Snippet]]
Step 2: Use Attributes for Weak Linking
Another effective approach is to declare the global variable using the weak attribute provided by GCC. This allows the linker to treat it differently, granting it the potential to be overridden while still being included.
[[See Video to Reveal this Text or Code Snippet]]
Step 3: For Windows Users
If you are working on a Windows platform, you can use the selectany specifier, which allows the symbol to be included but can also be optimized based on the compiler flags.
[[See Video to Reveal this Text or Code Snippet]]
Conclusion
Linking global variables from static libraries to dynamic libraries can be tricky but is certainly manageable. By forcing the usage of these variables through function references or using compiler attributes, you can ensure that crucial symbols are retained and recognized during linking. Always test your implementation thoroughly to confirm that the variable appears correctly in the shared library's .data section.
By employing the right techniques, you can effectively eliminate any linking issues that arise when integrating static and dynamic libraries in C++.
Видео How to Forcibly Link Dynamic Library to Static Library Global Variables канала vlogize
---
This video is based on the question https://stackoverflow.com/q/66977052/ asked by the user 'Narek Jaghinyan' ( https://stackoverflow.com/u/14794536/ ) and on the answer https://stackoverflow.com/a/75736013/ provided by the user 'Narek Jaghinyan' ( https://stackoverflow.com/u/14794536/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.
Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Forcibly link dynamic library to the global variable in the static library
Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/licensing
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/by-sa/4.0/ ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/by-sa/4.0/ ) license.
If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
---
How to Forcibly Link Dynamic Library to Static Library Global Variables
When working with C++ and building libraries, developers often encounter issues related to the proper linking of static and shared libraries. One common problem is ensuring that global variables defined in static libraries are also recognized in dynamic libraries. This guide will address how to tackle such an issue effectively.
The Problem
Imagine you've created a .c file that has a global string variable and compiled it into a static library. After linking this library to a shared library, you find that the global string symbol is missing. This issue occurs because the variable was not referenced within the dynamic library, leading the linker to discard it.
For example, you may have the following code definitions:
Static Library File
[[See Video to Reveal this Text or Code Snippet]]
Shared Library File
[[See Video to Reveal this Text or Code Snippet]]
You can see that even though you're declaring the external variable in the shared library, it doesn't show up in the .data section of the shared library as intended. The common approach using --whole-archive is not an option here.
The Solution: Making Symbols Visible
To ensure that the global variable from the static library appears in the shared library, you need to use specific techniques to reference it so that the linker keeps it in mind. Here’s a better method to do this:
Step 1: Define the Global Variable
Instead of directly defining a global variable, you can create a function that uses it. This usage guarantees that the linker does not discard the variable as unused.
[[See Video to Reveal this Text or Code Snippet]]
Step 2: Use Attributes for Weak Linking
Another effective approach is to declare the global variable using the weak attribute provided by GCC. This allows the linker to treat it differently, granting it the potential to be overridden while still being included.
[[See Video to Reveal this Text or Code Snippet]]
Step 3: For Windows Users
If you are working on a Windows platform, you can use the selectany specifier, which allows the symbol to be included but can also be optimized based on the compiler flags.
[[See Video to Reveal this Text or Code Snippet]]
Conclusion
Linking global variables from static libraries to dynamic libraries can be tricky but is certainly manageable. By forcing the usage of these variables through function references or using compiler attributes, you can ensure that crucial symbols are retained and recognized during linking. Always test your implementation thoroughly to confirm that the variable appears correctly in the shared library's .data section.
By employing the right techniques, you can effectively eliminate any linking issues that arise when integrating static and dynamic libraries in C++.
Видео How to Forcibly Link Dynamic Library to Static Library Global Variables канала vlogize
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17 марта 2025 г. 10:41:38
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