Example 12.3 | Class 12 Physics | Atoms | NCERT Solution | Sadhana Classes

In this video, we have explained Example 12.3 from Class 12 Physics Chapter 12 – Atoms as per the latest NCERT textbook.
This example helps you understand how to calculate the wavelength of spectral lines emitted in hydrogen atom transitions using Bohr’s energy level formula.

📘 In this video, you will learn:

Step-by-step solution of NCERT Example 12.3

Use of energy level difference
Δ
𝐸
=
𝐸
2
−
𝐸
1
ΔE=E
2
​

−E
1
​
Calculation of wavelength using
𝐸
=
ℎ
𝑐
𝜆
E=
λ
hc
​
Explanation of hydrogen emission spectrum

Useful for CBSE Class 12, NEET, and JEE Main aspirants

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📺 Watch Next:
👉 Example 12.2 – [https://youtu.be/Yjttx2_dGaQ]
👉 Example 12.4 – [https://youtu.be/Q6cnBLVPi9o]

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