SEE Exam Important Question | Prove that Sin20° Sin40° Sin60° Sin80° Sin120° = 3√3/32

In this video, we solve an important SEE exam question from trigonometry.
👉 Prove that:
Sin20° × Sin40° × Sin60° × Sin80° × Sin120° = 3√3 / 32
This type of question is very important for SEE Board Exams and helps you understand key trigonometric identities and concepts.
🎯 What you will learn:
Step-by-step proof
Use of trigonometric identities
Smart tricks for exams
Easy and clear explanation
📚 Perfect for:
SEE Students
Class 10 Maths
Board exam preparation
🔔 Don’t forget to Like, Share & Subscribe to Karna Maths Academy (Shrawan Sir) for more maths tricks and important questions.
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Видео SEE Exam Important Question | Prove that Sin20° Sin40° Sin60° Sin80° Sin120° = 3√3/32 канала Karna Maths Academy