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Infinite Series Trick 🔥 | Evaluate ∑ (-1)^{k+1} k(k+1)/k! | JEE Advanced Level Question#shorts

In this video, we solve a beautiful and concept-based infinite series problem frequently asked in JEE Advanced and other competitive exams.
We are asked to evaluate:
∑k=1∞(−1)k+1k(k+1)k!\sum_{k=1}^{\infty} (-1)^{k+1} \frac{k(k+1)}{k!}k=1∑∞(−1)k+1k!k(k+1)
This question beautifully combines:
• Alternating series
• Factorial manipulation
• Exponential series expansion
• Smart algebraic simplification
If you love solving problems using series expansion of eˣ, this one is for you!
Watch till the end to learn the fastest trick to crack such questions in exams without lengthy calculations.
📌 Perfect for:
JEE Advanced | JEE Main | ISI | CMI | NDA | Olympiad Aspirants
Don’t forget to Like 👍, Share 📤 and Subscribe 🔔 for more high-level maths problems!
#JEEAdvanced #InfiniteSeries #ExponentialSeries #MathsTricks #IITJEE #AlternatingSeries #JEE2026

Видео Infinite Series Trick 🔥 | Evaluate ∑ (-1)^{k+1} k(k+1)/k! | JEE Advanced Level Question#shorts канала VMATHS
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