Young’s Modulus CGS to MKS | What’s the Conversion Factor?

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In this 1.5-minute video, we decode a classic unit conversion trick: How to convert Young’s modulus from CGS to MKS system using just dimensional logic — a must-know for JEE, NEET, CET, and Class 11 Physics students.
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📚 Question Statement:
To determine Young’s modulus of a wire, the formula is:

Y = \frac{F L}{A \Delta L}

= original length

= area of cross-section

= change in length

= force applied
What is the conversion factor to convert Young’s modulus from CGS to MKS system?

Options:
(a) 1
(b) 10
(c) 0.1
(d) 0.01
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🧠 Concept Used:

Young’s modulus has the dimensions of pressure:

Y = \frac{\text{Force}}{\text{Area}} = \frac{MLT^{-2}}{L^2} = M L^{-1} T^{-2}

In CGS, unit of pressure is dyne/cm²
In MKS, unit of pressure is N/m² (Pascal)

Now:
So,

1 \, \text{dyne/cm}^2 = 0.1 \, \text{N/m}^2

✅ Conversion Factor: 0.1
✅ Correct Answer: (c) 0.1
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⏱️ Timestamps:

00:00 – Young’s Modulus Formula
00:30 – Identify Dimensions
00:50 – Use CGS vs MKS Units
01:30 – Final Conversion Factor
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🎯 Helpful For:

JEE Main / NEET Physics

MHT CET Physics

Class 11 Units & Measurements

CUET, NDA, SSC Exams
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