JEE Mains 2026 Physics Solution | 21st Jan Shift 2 | Rotation & Pulley Problem (Q37)

In this video, we solve a challenging Rotational Dynamics problem from the JEE Mains 2026 paper (21st Jan, Shift 2). The question involves calculating the acceleration of blocks connected over a composite pulley made of a rim and rods.

📝 Question Discussed:
The pulley shown in the figure is made using a thin rim and two rods of length equal to the diameter of the rim. The rim and each rod have a mass of M. Two blocks of mass of M and m are attached to two ends of a light string passing over the pulley, which is hinged to rotate freely in vertical plane about its center. The magnitudes of the acceleration experienced by the blocks is _____. (Assume no slipping of string on pulley).

Options:
1. (M-m)g / (2M+m)
2. (M-m)g / (M+m)
3. (M-m)g / [(11/3)M + m]
4. (M-m)g / [(8/3)M + m]

💡 Key Concepts Covered:
* System of Particles and Rotational Motion
* Moment of Inertia of Composite Bodies (Rim + Rods)
* Torque and Angular Acceleration (τ = Iα)
* No-Slipping Condition (a = Rα)
* Solving Coupled Equations of Motion

To solve this, we first determine the Moment of Inertia of the specialized pulley and then apply Newton's Laws for both translation and rotation.

👨‍🏫 About the Instructor:
Explained by Kanak Yadav, a graduate of NITK Surathkal.
Welcome to Physics Unlocked ⚛🔓 – your go-to destination for conceptual clarity in Physics for JEE Mains, JEE Advanced, and NEET.

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Видео JEE Mains 2026 Physics Solution | 21st Jan Shift 2 | Rotation & Pulley Problem (Q37) канала Physics Unlocked ⚛🔓