Array-2: Valid Anagram || LeetCode 242 || Three Solutions Explained
🌟 Solve the 'Valid Anagram' Problem with Three Efficient Solutions! 🌟
In this video, we tackle the "Valid Anagram" problem, a popular question in coding interviews. We’ll explore three different approaches to determine whether two strings are anagrams of each other. These approaches include character counting, sorting, and dynamic removal for a well-rounded understanding of string manipulation.
What You’ll Learn:
✅ Three different solutions for checking if two strings are anagrams.
✅ Using Counter from Python's collections module for elegant character counting.
✅ Sorting-based approach to check for anagram equality.
✅ Dynamic removal approach using lists for character matching.
✅ Time and space complexity analysis for all three solutions.
Problem Overview:
Two strings are considered anagrams if they contain the same characters with the same frequencies, but possibly in a different order. Given two strings s and t, your task is to determine whether t is an anagram of s.
📌 Applications:
1️⃣ Data Deduplication: Identifying duplicate entries that are rearranged versions of each other.
2️⃣ Cryptography: Validating strings for encryption or decryption consistency.
3️⃣ Search Engines: Checking for rearranged queries or typos.
Solution Overview
Solution 1: Dynamic Removal
For each character in s, check if it exists in t. If found, remove it; otherwise, return False.
Time Complexity:
O(n²): For every character in s, a search and removal is performed in t.
Space Complexity:
O(n): Space for the list t.
Solution 2: Sorting
Sort both strings and compare them. Anagrams will have identical sorted versions.
Time Complexity:
O(n log n): Sorting both strings.
Space Complexity:
O(n): Space for the sorted strings.
Solution 3: Character Counting
Use Python's Counter to count character frequencies in both strings and compare them.
Time Complexity:
O(n): Counting characters in both strings.
Space Complexity:
O(n): Space for the Counter objects.
Why Use Multiple Solutions?
Each solution showcases a different way to think about string problems:
Dynamic Removal: Brute force but intuitive for beginners.
Sorting: A straightforward and reliable approach.
Counter-Based: Optimal in terms of time and space efficiency.
👉 Try the Problem Yourself:
Valid Anagram - LeetCode
Why This Tutorial?
The 'Valid Anagram' problem is a fundamental exercise in string manipulation and algorithmic thinking. By the end of this tutorial, you’ll understand how to choose the best solution based on efficiency and problem constraints.
💡 Engage with Us:
Got questions or an alternative solution? Drop your thoughts in the comments! Let’s discuss and learn together.
👉 Don’t forget to LIKE, SUBSCRIBE, and SHARE this video to support the channel and stay tuned for more tutorials on algorithms, data structures, and coding tips!
Tags:
#StringAlgorithm, #ValidAnagram, #CharacterCounting, #SortingAlgorithm, #PythonProgramming, #CodingInterview, #Algorithms, #ProgrammingTutorial, #TechInterviews, #Cryptography, #SearchEngines, #DataDeduplication, #CodingChallenge, #Optimization
Видео Array-2: Valid Anagram || LeetCode 242 || Three Solutions Explained канала AlgorithmUz
In this video, we tackle the "Valid Anagram" problem, a popular question in coding interviews. We’ll explore three different approaches to determine whether two strings are anagrams of each other. These approaches include character counting, sorting, and dynamic removal for a well-rounded understanding of string manipulation.
What You’ll Learn:
✅ Three different solutions for checking if two strings are anagrams.
✅ Using Counter from Python's collections module for elegant character counting.
✅ Sorting-based approach to check for anagram equality.
✅ Dynamic removal approach using lists for character matching.
✅ Time and space complexity analysis for all three solutions.
Problem Overview:
Two strings are considered anagrams if they contain the same characters with the same frequencies, but possibly in a different order. Given two strings s and t, your task is to determine whether t is an anagram of s.
📌 Applications:
1️⃣ Data Deduplication: Identifying duplicate entries that are rearranged versions of each other.
2️⃣ Cryptography: Validating strings for encryption or decryption consistency.
3️⃣ Search Engines: Checking for rearranged queries or typos.
Solution Overview
Solution 1: Dynamic Removal
For each character in s, check if it exists in t. If found, remove it; otherwise, return False.
Time Complexity:
O(n²): For every character in s, a search and removal is performed in t.
Space Complexity:
O(n): Space for the list t.
Solution 2: Sorting
Sort both strings and compare them. Anagrams will have identical sorted versions.
Time Complexity:
O(n log n): Sorting both strings.
Space Complexity:
O(n): Space for the sorted strings.
Solution 3: Character Counting
Use Python's Counter to count character frequencies in both strings and compare them.
Time Complexity:
O(n): Counting characters in both strings.
Space Complexity:
O(n): Space for the Counter objects.
Why Use Multiple Solutions?
Each solution showcases a different way to think about string problems:
Dynamic Removal: Brute force but intuitive for beginners.
Sorting: A straightforward and reliable approach.
Counter-Based: Optimal in terms of time and space efficiency.
👉 Try the Problem Yourself:
Valid Anagram - LeetCode
Why This Tutorial?
The 'Valid Anagram' problem is a fundamental exercise in string manipulation and algorithmic thinking. By the end of this tutorial, you’ll understand how to choose the best solution based on efficiency and problem constraints.
💡 Engage with Us:
Got questions or an alternative solution? Drop your thoughts in the comments! Let’s discuss and learn together.
👉 Don’t forget to LIKE, SUBSCRIBE, and SHARE this video to support the channel and stay tuned for more tutorials on algorithms, data structures, and coding tips!
Tags:
#StringAlgorithm, #ValidAnagram, #CharacterCounting, #SortingAlgorithm, #PythonProgramming, #CodingInterview, #Algorithms, #ProgrammingTutorial, #TechInterviews, #Cryptography, #SearchEngines, #DataDeduplication, #CodingChallenge, #Optimization
Видео Array-2: Valid Anagram || LeetCode 242 || Three Solutions Explained канала AlgorithmUz
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27 января 2025 г. 12:28:56
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