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Q) If lim(𝑥→0) (3+𝛼sin𝑥+𝛽cos𝑥+log_𝑒 (1−𝑥))/(3tan^2 𝑥) =1/3, then 2𝛼−𝛽#maths #jee2025

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Q) If lim(𝑥→0) (3+𝛼sin𝑥+𝛽cos𝑥+log_𝑒 (1−𝑥))/(3tan^2 𝑥) =1/3, then 2𝛼−𝛽 is equal to:(a) 2(b) 7(c) 5(d) 1
JEE MAIN PYQ 2025 ( 3 April - shift 2 ) Limits and continuity PYQ 2025 #maths Class12 #jee2026
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Видео Q) If lim(𝑥→0) (3+𝛼sin𝑥+𝛽cos𝑥+log_𝑒 (1−𝑥))/(3tan^2 𝑥) =1/3, then 2𝛼−𝛽#maths #jee2025 канала Shivang Maths Academy JEE
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