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Greedy Algorithm Made Easy | LeetCode 1221

In this video, we solve LeetCode 1221 – “Split a String in Balanced Strings” step by step.

You’ll learn:

* What balanced strings mean
* Greedy approach explained simply
* Count balancing technique
* Efficient single-pass solution

Problem:
Balanced strings contain equal numbers of 'L' and 'R' characters.

Given a balanced string s, split it into the maximum number of balanced substrings.

Return the maximum number of split balanced strings.

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⏱ Time Complexity: O(n)
💾 Space Complexity: O(1)

💡 Key Concept:
Traverse the string and maintain a balance counter:

* Increment for 'R'
* Decrement for 'L'

Whenever balance becomes 0, one balanced substring is found.

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This is a beginner-friendly greedy problem commonly used to build problem-solving intuition.

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🔗 Connect with me:
LinkedIn: https://www.linkedin.com/in/dashrat-rajpurohit/
X (Twitter): https://x.com/Dashrat_Singh_
GitHub: https://github.com/DashratRajpurohit

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If you're preparing for DSA or coding interviews, understanding greedy patterns is important.

#leetcode #greedy #strings #codinginterview #dsa

Видео Greedy Algorithm Made Easy | LeetCode 1221 канала Dashrat Singh
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