Fixing Two Nodes of a BST | GFG Solution in C++ | Recover Binary Search Tree Explained

Problem Statement:

Given the root of a Binary Search Tree in which exactly two nodes have been swapped by mistake, restore the BST by swapping those two nodes back. The structure of the tree must remain unchanged, and all corrections should be made in the original tree.

Example:

Input:
root = [10, 5, 8, 2, 20]

Output:
1

Explanation:
The nodes with values 20 and 8 were swapped. After swapping them back, the Binary Search Tree becomes valid again.

Problem Link:
https://www.geeksforgeeks.org/problems/fixed-two-nodes-of-a-bst/1

In this video, we solve the GeeksforGeeks problem "Fixing Two Nodes of a BST" using an efficient inorder traversal approach. We identify the misplaced nodes by detecting violations in the inorder sequence and then swap their values to restore the Binary Search Tree. The video includes intuition, algorithm, dry run, time complexity analysis, and complete C++ implementation.

Topics Covered:
Binary Search Tree
Recover BST
Inorder Traversal
Tree Traversal
Recursion
Tree Problems
GeeksforGeeks Solutions

#geeksforgeeks #gfg #dsa #cpp #bst #binarysearchtree #trees #inordertraversal #codinginterview #algorithms #programming

Fixing Two Nodes of a BST, GFG Solution, GeeksforGeeks, Recover Binary Search Tree, Binary Search Tree, BST, Inorder Traversal, Tree Problems, DSA, C++, Coding Interview Preparation, Algorithms, Data Structures, Competitive Programming

Видео Fixing Two Nodes of a BST | GFG Solution in C++ | Recover Binary Search Tree Explained канала SCIENCE IN FRONT OF YOU