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Maximum Profit from Topological Ordering | DAG + Bitmask DP | LeetCode Hard C++ Solution

In this video, we solve a **LeetCode Hard problem** on **Directed Acyclic Graph (DAG)** using **Bitmask Dynamic Programming (DP)**.

🔥 Problem statement:

* You are given a DAG with `n` nodes and scores.
* Process nodes in a valid **topological order**.
* Each node’s score is multiplied by its position (1-based).
* Maximize the total profit.

✅ Constraints: `n 22`, which makes **Bitmask DP (O(n \* 2^n))** the perfect approach.
✅ Learn how to use **bitmasking + DP** to solve ordering problems with dependencies.
✅ Full **C++ code implementation** with step-by-step explanation.

**Example:**

```
Input:
n = 3
edges = [[0,1],[0,2]]
score = [1,6,3]

Output: 25
```

📌 Topics Covered:

* DAG & Topological Sorting
* Bitmask Dynamic Programming
* Maximum Profit Calculation
* LeetCode Hard Problem Solution in C++

💡 Don’t forget to **Like, Share, and Subscribe** for more **C++ coding problems, LeetCode solutions, and interview prep content**!

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#LeetCode #CPlusPlus #DynamicProgramming #BitmaskDP #GraphAlgorithms #TopologicalSort #CompetitiveProgramming #CodingInterview #LeetCodeHard #DAG #Algorithms

Видео Maximum Profit from Topological Ordering | DAG + Bitmask DP | LeetCode Hard C++ Solution канала Coding theory
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