Construct Binary Search Tree from Preorder | BST Construction | Data structures

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- The first element of preorder array will contain the root element as it's preorder so create a node of this value
- Now traverse from first of array & find the value lesser than node value which we just created
- Let's say we find the value at ith index
- Now all values from start to i will be in left sub tree & from i + 1 to end - 1 will be in right subtree
- Again recursively call the function with node.left = create(arr, start, i) & node.right = create(arr, i+1, end-1)
- return node from function

Time Complexity: O(n), where n is total number of elements in array
Space Complexity: O(1)

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