Загрузка...

LeetCode 1217 | Minimum Cost to Move Chips to The Same Position | Easy Problem | C++ Solution

In this video, I explain the problem step-by-step, discuss the optimal greedy approach, and implement the solution live while coding.

🚀 Problem: LeetCode 1217 – Minimum Cost to Move Chips to The Same Position

🧠 Approach:

Observe the movement cost rules:

Moving a chip by 2 positions costs 0
Moving a chip by 1 position costs 1

Count:

Number of chips at even positions
Number of chips at odd positions

To make all chips meet at the same position:

Move the smaller group to the larger group

Return the minimum of:

even count
odd count

⏱ Time Complexity: O(n)
📦 Space Complexity: O(1)

🔗 GitHub Repository:
https://github.com/VishwaPatel892/Leetcode_Solutions

👨‍💻 LeetCode Profile:
https://leetcode.com/u/vishwa0102/

💼 LinkedIn:
https://www.linkedin.com/in/vishwa-patel-9bab9639a

📝 Notes:

Greedy observation-based problem
Parity (odd/even) is the key concept
Moving by 2 positions is free
Simple and efficient one-pass solution
#leetcode #leetcode1217 #dsa #algorithms #coding #programming #codinginterview #interviewprep #greedy #math #leetcodeeasy #problemSolving #learncoding #codewithme #developerlife #tech #placements #softwareengineer #codinglife #100daysofcode

👍 Like | Comment | Subscribe for more LeetCode solutions!

Видео LeetCode 1217 | Minimum Cost to Move Chips to The Same Position | Easy Problem | C++ Solution канала Vishwa Patel
Яндекс.Метрика
Все заметки Новая заметка Страницу в заметки
Страницу в закладки Мои закладки
На информационно-развлекательном портале SALDA.WS применяются cookie-файлы. Нажимая кнопку Принять, вы подтверждаете свое согласие на их использование.
О CookiesНапомнить позжеПринять