LeetCode 7 Easy Explanation | Reverse Integer

🔥 LeetCode 7 - Reverse Integer | C++ Solution Explained

In this video, I solve LeetCode Problem 7: "Reverse Integer" using an efficient mathematical approach in C++.

The problem asks us to reverse the digits of a signed 32-bit integer while handling overflow conditions correctly. We will understand the logic step-by-step and implement an optimized solution with proper explanation.

🧠 Approach Used:
We repeatedly extract the last digit of the number using the modulo (%) operator and build the reversed number.

Example:
123 → 321

Before updating the reversed number, we check for integer overflow to ensure the result stays within the 32-bit signed integer range.

✅ Time Complexity: O(log n)
✅ Space Complexity: O(1)

⏱️ Timeline:
00:00 Introduction
00:20 Problem Statement
00:50 Mathematical Logic
01:40 C++ Code Explanation
02:40 Overflow Handling
03:00 Complexity Analysis & Conclusion

💻 Language:
C++

🎯 Problem Link:
https://leetcode.com/problems/reverse-integer/

🌐 Connect With Me:

💼 LinkedIn: https://www.linkedin.com/in/harshitpandya2911/
🐙 GitHub: https://github.com/harshitpandya-cg/LeetCode-Solutions/tree/main/0007-reverse-integer
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Видео LeetCode 7 Easy Explanation | Reverse Integer канала Harshit Pandya