Kth common ancestor in BST(potdgfgtoday+cpp code+java code)

Given a BST with n n always more than 2 nodes, find the kth common ancestor of nodes x and y in the given tree. Return -1 if kth ancestor does not exists.
Nodes x and y will always be present in input BST, and x != y.
java solution code:https://github.com/Varthya/kth-common-ancestors-in-bst-java-code/tree/main
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Видео Kth common ancestor in BST(potdgfgtoday+cpp code+java code) канала mathematics_rajkumar