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Compare Version Numbers — LeetCode #165 | Python Algorithm Visualization

## Description
Step-by-step algorithm visualization for LeetCode #165 (Compare Version Numbers). The solution parses both version strings on the fly without splitting, extracting integer revisions between dots and comparing them pairwise. Leading zeros are naturally handled by the integer conversion logic, and missing revisions in a shorter version are treated as zero.

*Complexity Analysis:*
- Time Complexity: O(max(m, n)) — where m and n are the lengths of version1 and version2. Each character is processed exactly once.
- Space Complexity: O(1) — only a few integer variables are used, with no additional data structures.

*Timestamps:*
0:00 — Problem Setup & Two-Pointer Logic
0:08 — Main Cycle
1:59 — Integer Comparison & Early Return

*Resources:*
Telegram: https://t.me/benabub_algoviz
GitHub: https://github.com/benabub
Support channel: https://boosty.to/benabub

Видео Compare Version Numbers — LeetCode #165 | Python Algorithm Visualization канала Benabub
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