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A Simple GCD Problem (Easy Version) - Codeforces Round 1089 (Div. 2) |
Detailed explanation and solution for "A Simple GCD Problem (Easy Version)" from Codeforces Round 1089 (Div. 2).
This video covers the full thought process to achieve the maximum number of operations while keeping subarray GCDs invariant. We break down the condition gcd(a_l...a_r) = gcd(a'_l...a'_r), derive the optimized greedy approach, and implement it with a time complexity of O(N log(max(A_i))).
#Codeforces #CompetitiveProgramming #Algorithm #DataStructures #GCD #CodeforcesSolution #ProgrammingTutorial #CodingLife #LearnToCode
Видео A Simple GCD Problem (Easy Version) - Codeforces Round 1089 (Div. 2) | канала TrozCode
This video covers the full thought process to achieve the maximum number of operations while keeping subarray GCDs invariant. We break down the condition gcd(a_l...a_r) = gcd(a'_l...a'_r), derive the optimized greedy approach, and implement it with a time complexity of O(N log(max(A_i))).
#Codeforces #CompetitiveProgramming #Algorithm #DataStructures #GCD #CodeforcesSolution #ProgrammingTutorial #CodingLife #LearnToCode
Видео A Simple GCD Problem (Easy Version) - Codeforces Round 1089 (Div. 2) | канала TrozCode
Codeforces Codeforces Solution A Simple GCD Problem Easy Version Codeforces Round 1089 Div 2 Competitive Programming Algorithm Design Data Structures Greatest Common Divisor GCD Problem Coding Tutorial Programming Problem Solving C++ Algorithm Python Algorithm Time Complexity Codeforces Educational Dynamic Programming Competitive Coding Learn Coding. Codeforces Round 1089 (Div. 2) Codeforces Round 1089 (Div. 2) c1 C1. A Simple GCD Problem
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