asyncio.timeout for async generator does not work

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Why does asyncio.timeout not work when wrapping async generator like in example below?
async def generate_many_numbers():
for i in range(1000000000):
yield i

async def main2():
async with asyncio.timeout(1):
async for number in generate_many_numbers():
print(number)

asyncio.run(main2())

async def generate_many_numbers():
for i in range(1000000000):
yield i

async def main2():
async with asyncio.timeout(1):
async for number in generate_many_numbers():
print(number)

asyncio.run(main2())

Can it be the same issue which is described here? https://peps.python.org/pep-0789/
https://peps.python.org/pep-0789/
I have noticed that adding async dummy sleep helps...
async def generate_many_numbers():
for i in range(1000000000):
await asyncio.sleep(0)
yield i

async def iterate_through_numbers():
async for number in generate_many_numbers():
print(number)

async def main2():
async with asyncio.timeout(1):
async for number in generate_many_numbers():
print(number)

async def main3():
try:
await asyncio.wait_for(iterate_through_numbers(), timeout=1)
except asyncio.TimeoutError:
print("The task timed out!")

async def generate_many_numbers():
for i in range(1000000000):
await asyncio.sleep(0)
yield i

async def iterate_through_numbers():
async for number in generate_many_numbers():
print(number)

async def main2():
async with asyncio.timeout(1):
async for number in generate_many_numbers():
print(number)

async def main3():
try:
await asyncio.wait_for(iterate_through_numbers(), timeout=1)
except asyncio.TimeoutError:
print("The task timed out!")
Tags: python,async-await,python-asyncio,generatorSource of the question:
https://stackoverflow.com/questions/78986047

Question and source license information:
https://meta.stackexchange.com/help/licensing
https://stackoverflow.com/

Видео asyncio.timeout for async generator does not work канала Emrah KAYA