C++ Program to Check for Leap Years #shorts

In this C++ program, we demonstrate how to determine whether a given year is a leap year or not. The program checks a list of years (stored in the `arr` array) and prints a message indicating whether each year is a leap year or not. It utilizes the leap year rule, which states that a year is a leap year if it is divisible by 4 but not divisible by 100, or if it is divisible by 400.

Here's a breakdown of how the program operates:

1. An integer array `arr` is initialized with a list of years: 2000, 2006, and 2024.

2. The program calculates the number of elements in the `arr` array (n) using the `sizeof` operator and dividing it by the size of a single array element.

3. A `for` loop is used to iterate through each year in the array.

4. Inside the loop, the program checks whether the current year (arr[i]) meets the conditions for being a leap year:
- `(arr[i] % 4 == 0)` checks if the year is divisible by 4.
- `(arr[i] % 100 != 0 || arr[i] % 400 == 0)` checks if the year is not divisible by 100 or is divisible by 400. This condition ensures that years like 2000, which are divisible by 400, are correctly identified as leap years.

5. If the conditions are met, the program prints a message indicating that the year is a leap year; otherwise, it prints a message stating that the year is not a leap year.

6. The program repeats this process for each year in the array.

7. The output of the program is a list of messages indicating whether each year in the array is a leap year or not.

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