Major Product in Reaction – Concept of Elimination & Free Radical Polymerization (2019 Question)

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Correct Answer: (b)
Precise Explanation:
Step 1: Alcoholic KOH → Elimination (E2)
The given side-chain chloride undergoes β-elimination with alcoholic KOH.
This forms an alkene (double bond) in the side chain.
Product formed: substituted styrene-type alkene (vinyl group attached to benzene ring with Cl still on ring).
Step 2: Free Radical Polymerisation
The alkene undergoes free radical addition polymerization.
Polymerization happens across the C=C double bond, not on the benzene ring.
The substituents (CH₃ and phenyl ring with Cl) remain attached to the polymer backbone.
Key Observations:
No OH formation → options (c) and (d) eliminated.
Cl on benzene ring remains unchanged (no substitution).
Polymer repeating unit must reflect alkene addition pattern.
👉 Only option (b) correctly represents the polymer formed.

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