Exercise 2(c) Functions Explained in Telugu | Domain and Range | Inter 1st Year & Class 11 Maths

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In this video, we explain Exercise 2(c) from Chapter 2: Relations and Functions of Intermediate 1st Year Mathematics, which is also helpful for CBSE Class 11 students. We cover key concepts like domain and range, function definition, real-life applications of functions, and how to evaluate or identify a function.

🎯 In this video, you will learn in Telugu:
✔️ What is a Function?
✔️ Relation vs Function
✔️ How to identify a function from a set of ordered pairs
✔️ Domain and Range of different functions
✔️ Understanding absolute value, square root, and polynomial functions
✔️ Real-life example: Temperature conversion
✔️ Evaluating functions like f(x) = 2x – 5
✔️ Range finding using algebra
✔️ Difference quotient concept

📚 Examples Covered:
🔹 Find domain and range of f(x) = –|x|
🔹 Find domain and range of f(x) = √(9 – x²)
🔹 Evaluate f(x) = 2x – 5 at x = 0, 7, –3
🔹 Find range of:
  (i) f(x) = 2 – 3x
  (ii) f(x) = x² + 2
  (iii) f(x) = x
🔹 Determine if relations like {(2,1), (5,1), (8,1)} are functions
🔹 Use real-life formula: t(C) = (9C/5) + 32
🔹 Evaluate t(0), t(28), t(–10), and find C when t(C) = 212
🔹 Function difference: (f(1) – f(1))/(1.1 – 1) where f(x) = x²

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▶️ Watch Previous Exercises & Playlist:
👉 https://youtube.com/playlist?list=PLMGpkMSLDkxSZtLoKmnvRGrH0O0AyNnAY&si=yWBD9tXsJcGZkQGa

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Disclaimer: ఈ వీడియో Intermediate 1st Year మరియు CBSE Class 11 Mathematics syllabus ఆధారంగా తయారుచేయబడింది. ఇది విద్యార్థుల కోసం సరళమైన ఉపాధానంగా రూపొందించబడినది. ఇందులోని వివరణలు విద్యార్ధులకు concept అర్థమయ్యేలా సులభంగా చెప్పబడ్డాయి. Academic accuracy కోసం దయచేసి మీ పాఠ్యపుస్తకాలు మరియు subject teacher ను సంప్రదించండి. This video is for educational purposes only.

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