LeetCode 58: Length of Last Word | Simple String Traversal Explained

In this video, we solve **LeetCode 58 – Length of Last Word** using a clean and efficient string traversal approach.

We iterate from the end of the string to directly find the last word and calculate its length.

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💡 **What You’ll Learn**
• How to traverse strings from the end
• Ignoring trailing spaces efficiently
• Finding the last word without extra storage
• Time & Space Complexity explained clearly

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🧠 **Concepts Covered**
• Strings
• Traversal techniques
• Edge case handling
• Efficient iteration logic

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📌 **Problem Summary**
Given a string consisting of words and spaces, return the length of the last word in the string.

A word is defined as a sequence of non-space characters.

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⚡ **Approach Used in This Video**
We start traversing the string from the back:
• First, skip all trailing spaces
• Then count characters until another space is found

The count gives the length of the last word.

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⏱ **Complexity**
Time Complexity: O(n)
Space Complexity: O(1)

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🎯 **Why This Matters**
This problem helps you:
• Improve string manipulation skills
• Handle edge cases cleanly
• Build efficient traversal logic for interviews

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🔗 **Connect With Me**
GitHub: https://github.com/Ritesh007-max
Twitter (X): https://x.com/RiteshGabale007
LinkedIn: https://www.linkedin.com/in/ritesh-gabale-59a2b5365/
Portfolio: https://ritesh-portfolio-v06.netlify.app/

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📈 **Tags**
#leetcode #dsa #strings #codinginterview #programming #cplusplus

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Видео LeetCode 58: Length of Last Word | Simple String Traversal Explained канала Ritesh