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Remove Duplicates from Sorted Array | Two Pointer Approach Explained | C++ language
In this video, we solve the "Remove Duplicates from Sorted Array" problem from LeetCode using the Two Pointer Approach.
--------------------------------------------------
🔍 Problem Summary:
Given a sorted array, remove duplicates in-place such that each unique element appears only once and return the number of unique elements.
Example:
Input: [1,1,2,2,3]
Output: 3
Valid Final Array:
[1,2,3]
--------------------------------------------------
🧠 Approach:
1. Use two pointers:
- `i` tracks unique elements
- `j` traverses the array
2. Compare current elements.
3. If a new unique element is found:
- move `i`
- place the unique value at index `i`
4. Return `i + 1` as the count of unique elements.
⏱ Time Complexity: O(n)
📦 Space Complexity: O(1)
--------------------------------------------------
💻 Concepts Covered:
- Two Pointer Technique
- Sorted Arrays
- In-place Array Modification
- Array Traversal
- Dry Run Explanation
--------------------------------------------------
🔗 GitHub:
👉 https://github.com/Prajapati-Krishna18
👨💻 LeetCode Profile:
👉 https://leetcode.com/u/ZcBAozJjEk/
💼 LinkedIn:
👉 https://www.linkedin.com/in/krishna-prajapati-45ba713ab/
--------------------------------------------------
📝 Notes:
- One of the most important beginner DSA problems
- Frequently asked in coding interviews
- Great problem to understand two pointers
- Full dry run explained step-by-step
--------------------------------------------------
👍 If you enjoyed the video:
- Like 👍
- Share 🔁
- Subscribe 🔔
📌 Comment the next LeetCode problem you want explained!
#leetcode #cpp #dsa #twopointers #arrays #codinginterview #beginners
Видео Remove Duplicates from Sorted Array | Two Pointer Approach Explained | C++ language канала Krishna Prajapati
--------------------------------------------------
🔍 Problem Summary:
Given a sorted array, remove duplicates in-place such that each unique element appears only once and return the number of unique elements.
Example:
Input: [1,1,2,2,3]
Output: 3
Valid Final Array:
[1,2,3]
--------------------------------------------------
🧠 Approach:
1. Use two pointers:
- `i` tracks unique elements
- `j` traverses the array
2. Compare current elements.
3. If a new unique element is found:
- move `i`
- place the unique value at index `i`
4. Return `i + 1` as the count of unique elements.
⏱ Time Complexity: O(n)
📦 Space Complexity: O(1)
--------------------------------------------------
💻 Concepts Covered:
- Two Pointer Technique
- Sorted Arrays
- In-place Array Modification
- Array Traversal
- Dry Run Explanation
--------------------------------------------------
🔗 GitHub:
👉 https://github.com/Prajapati-Krishna18
👨💻 LeetCode Profile:
👉 https://leetcode.com/u/ZcBAozJjEk/
💼 LinkedIn:
👉 https://www.linkedin.com/in/krishna-prajapati-45ba713ab/
--------------------------------------------------
📝 Notes:
- One of the most important beginner DSA problems
- Frequently asked in coding interviews
- Great problem to understand two pointers
- Full dry run explained step-by-step
--------------------------------------------------
👍 If you enjoyed the video:
- Like 👍
- Share 🔁
- Subscribe 🔔
📌 Comment the next LeetCode problem you want explained!
#leetcode #cpp #dsa #twopointers #arrays #codinginterview #beginners
Видео Remove Duplicates from Sorted Array | Two Pointer Approach Explained | C++ language канала Krishna Prajapati
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8 мая 2026 г. 10:08:17
00:12:58
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