JPC Fractal 36 - Music "Bette Davis Eyes" by Kim Carnes
I use this formular: Z ← Zⁿ + F(C). Where n≥2 and F(C) is a complex function of the screen coordinate C. If F does not depend on Z, it means that F(C) can be calculated before the starting of the iteration process. Which makes calculations faster.
In this video F(C) = p∙(³C)ᵐ + u.
m, p and u are reals numbers. ³C is a TETRATION with the high of 3: ³C = C^(C^C).
I make the following morphing:
(n, m, p, u) = (2, 1, 2, 0) → (2½, 1, 2, 0) → (3, 1, 2, 0) → (3, 2, ½, 0) → (3, 3, 1, -½) → (3, 2, 1, -½) →
(3, 2, 1.002, -½) → (3, 2, 1.0025, -0.5002) → (3, 1, 1.0025, -0.5003) → (3, 2, 1.0035, -½) →
(3, 4, 1, -½) → (3, 8, 2, -½) → (3, 8, 2½, -0.45) → (3, 1, 2, 0) → (3, 1, 2, 0) → (3.000001, 1, 2, 0) → (3.00001, 1, 2, 0) → (3.00004, 1, 2, 0) → (3.00005, 1, 2, 0) → (3.00006, 1, 2, 0)
Видео JPC Fractal 36 - Music "Bette Davis Eyes" by Kim Carnes канала Jens-Peter Christensen
In this video F(C) = p∙(³C)ᵐ + u.
m, p and u are reals numbers. ³C is a TETRATION with the high of 3: ³C = C^(C^C).
I make the following morphing:
(n, m, p, u) = (2, 1, 2, 0) → (2½, 1, 2, 0) → (3, 1, 2, 0) → (3, 2, ½, 0) → (3, 3, 1, -½) → (3, 2, 1, -½) →
(3, 2, 1.002, -½) → (3, 2, 1.0025, -0.5002) → (3, 1, 1.0025, -0.5003) → (3, 2, 1.0035, -½) →
(3, 4, 1, -½) → (3, 8, 2, -½) → (3, 8, 2½, -0.45) → (3, 1, 2, 0) → (3, 1, 2, 0) → (3.000001, 1, 2, 0) → (3.00001, 1, 2, 0) → (3.00004, 1, 2, 0) → (3.00005, 1, 2, 0) → (3.00006, 1, 2, 0)
Видео JPC Fractal 36 - Music "Bette Davis Eyes" by Kim Carnes канала Jens-Peter Christensen
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