Special Array I | 2 Approaches | Leetcode 3151 | codestorywithMIK

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Leetcode 3152 (Special Array II) - https://www.youtube.com/watch?v=powGdCI0afg

Hi Everyone, this is the 64th video of our Playlist "Leetcode Easy".
Now we will be solving an easy  practice problem on Array  - Special Array I | 2 Approaches | Leetcode 3151 | codestorywithMIK

Problem Name : Special Array I | 2 Approaches | Leetcode 3151 | codestorywithMIK
Company Tags : will update later
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Arrays/Leetcode%20Easy/Special%20Array%20I.cpp
Leetcode Link : https://leetcode.com/problems/special-array-i

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Video Summary :
Approach-1 (Simple Iteration):
We iterate through the array and check if consecutive elements have the same even or odd nature. If we find such a pair, we return false. Otherwise, the array is special.

Approach-2 (Using Bit Magic):
Instead of using modulo, we leverage bitwise & 1 to determine whether a number is even or odd. The rest of the logic remains the same—if consecutive elements have the same parity, return false, else return true.

 Timelines 
00:00 - Introduction
00:24 - Motivation
00:54 - Problem Explanation
02:12 - Approach-1 (Simple loop)
03:46 - Approach-2 (Using Bit Magic)
06:30 - Coding it up
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