Jewels and Stones | LeetCode Easy | Hash Set Approach | C++

🔹 Problem: Jewels and Stones (LeetCode)

In this video, we solve the Jewels and Stones problem using a hash set approach.

The task is to count how many stones are also jewels.

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🔹 Approach:

We use a hash set for fast lookup.

Steps:
1. Store all jewel characters in a set
2. Traverse the stones string
3. If character exists in set:
- Increase count
4. Return final count

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🔹 Key Idea:

Hash sets provide constant time lookup, making the solution efficient.

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🔹 Time Complexity:
O(n + m)

🔹 Space Complexity:
O(n)

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🔗 GitHub: https://github.com/DhruvOzha85
🔗 LeetCode Profile: https://leetcode.com/u/DhruvOzha/
🔗 LinkedIn: https://www.linkedin.com/in/dhruv-ozha-bb378639b/

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📌 Notes:
- Beginner-friendly hash set problem
- Helps understand fast lookup concepts
- Important for interview preparation

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Видео Jewels and Stones | LeetCode Easy | Hash Set Approach | C++ канала Dhruv Ozha