JEE Advanced 2021 Physics Q8 RC Circuit q2 #JEEADVANCEDPYQ #jeeadvanced #jeeadvance2021 #jeeadvance

JEE Advanced 2021 Paper-1 Physics Question 8 - Solved with step-by-step animated explanation!
Continuing from Q7, when the switch S is moved to position Q, the circuit reconfigures. In the new steady state, the current is I = 2/3 A and the voltage across the capacitor becomes V_A = 2/3 V, giving q2 = 2/3 microCoulombs = 0.67 microC.
This video covers:
- Circuit reconfiguration with switch position - New steady-state analysis
- Kirchhoff's laws for modified circuit
- Charge redistribution on capacitor
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