JEE Advanced 2020 Hidden Tricks | Function Sum + Functional Equation Solved Smartly

🎯 JEE Advanced 2020 Two Beautiful Questions Solved with Smart Tricks!

In this video we cover two high-weightage tricky questions from JEE Advanced 2020:

1️⃣ Function f(x) = 4ˣ / (4ˣ + 2)
Find: f(1/40) + f(2/40) + ... + f(39/40) - f(1/2)

2️⃣ Functional Equation: f(x-1) + f(x+1) = √3 f(x)
Given f(5) = 10, find g'(x) where g(x) = sum f(5 + 12r) from r=0 to 99
These two questions test deep conceptual understanding of functions and recurrence. Perfect for JEE 2026 & 2027 aspirants who want to solve "impossible" problems quickly.

💡 Key Takeaways:
- Powerful pairing technique in functions
- How to handle linear homogeneous recurrence relations

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