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Jee-main series 2025#22 jan morning shift#Differential Equation#72
#https://youtu.be/jQvSF2x_rWM
72. Let x= x(y) be the solution of the differential equation
𝒚^𝟐 𝒅𝒙+(𝒙−𝟏/𝒚)𝒅𝒚=𝟎. If x(1) =1, then 𝒙(𝟏/𝟐) is:
(1) 𝟏/𝟐 +e (2) 𝟑/𝟐 +e (3) 3-e (4) 3+e
Видео Jee-main series 2025#22 jan morning shift#Differential Equation#72 канала TCM (THE CONCEPT OF MATHEMATICS)
72. Let x= x(y) be the solution of the differential equation
𝒚^𝟐 𝒅𝒙+(𝒙−𝟏/𝒚)𝒅𝒚=𝟎. If x(1) =1, then 𝒙(𝟏/𝟐) is:
(1) 𝟏/𝟐 +e (2) 𝟑/𝟐 +e (3) 3-e (4) 3+e
Видео Jee-main series 2025#22 jan morning shift#Differential Equation#72 канала TCM (THE CONCEPT OF MATHEMATICS)
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20 августа 2025 г. 18:34:10
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