Romberg Integration | Numerical Mathematics
There is a slight mistake in n=1.
I have written sin(π/2) instead of sin(π).
So it should be (for n=1):
=(π/2)*[sin(0)+sin(π)] = 0
Видео Romberg Integration | Numerical Mathematics канала The Infinite Math
I have written sin(π/2) instead of sin(π).
So it should be (for n=1):
=(π/2)*[sin(0)+sin(π)] = 0
Видео Romberg Integration | Numerical Mathematics канала The Infinite Math
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