Class 11 Physics: Vectors Lec 2 | Magnitude & Direction (2D & 3D) 🔥 | JEE/NEET

🚀 Welcome back to Lecture 02 of our Class 11 VECTORS Series!
In the previous lecture, we covered the absolute basics. Today, we are stepping up the game! In this video, we deep dive into how to find the exact Magnitude (Size) and Direction (Angle) of any vector, with a special focus on 2D space, and then extend the concept to 3D formulas.
If you want to understand how vectors actually work in Cartesian coordinates (x, y, z axes), this lecture is an absolute must-watch for CBSE, JEE, and NEET aspirants!
🔥 What You Will Learn in This Video:
Vectors in 2D Space: How to represent a vector in a plane using components (Ax i-cap + Ay j-cap).
Magnitude in 2D: The mathematical derivation of finding a vector's length using the Pythagorean theorem: Magnitude = Square root of (Ax^2 + Ay^2).
Direction in 2D: How to find the angle (Theta) of a vector with the axis using basic trigonometry: tan(Theta) = Ay / Ax.
Extension to 3D Space: Moving from a plane to space (Ax i-cap + Ay j-cap + Az k-cap).
Magnitude in 3D Formula: Understanding the formula with its corresponding relations: Magnitude = Square root of (Ax^2 + Ay^2 + Az^2).

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💬 Got Doubts? Drop them in the comments below! Can you find the magnitude of vector A = 3i + 4j + 5k? Solve it and comment your answer!
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Видео Class 11 Physics: Vectors Lec 2 | Magnitude & Direction (2D & 3D) 🔥 | JEE/NEET канала Sojourn Institute