NEET 2018 PYQs | NEET PHYSICS Question 433 | how to solve combination of resistances |

⚡🔗 NEET 2018 PYQ – Combination of n Resistances Using a Single Wire 🔗⚡

A very important and logical formula-based question from Current Electricity! 🎯

🔍 Key Concept:

If a wire is cut into n equal parts, resistance of each part becomes:

R' = \frac{R}{n}

👉 Because:
R \propto L

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📌 When n Pieces are Connected in Series:

R_s = n \times \frac{R}{n} = R

✔ Total resistance remains same

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📌 When n Pieces are Connected in Parallel:

R_p = \frac{R}{n^2}

✔ Resistance decreases greatly

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✅ Final Idea:

💡 Cutting wire changes resistance because length changes

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✨ Shortcut Tip:
Cut into n parts →
Each part:
\frac{R}{n}

Parallel combination:
\frac{R}{n^2}

Very important NEET trick question 🎯

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