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Find the Peak Element in a 2D Matrix | GFG POTD | Binary Search | Java

In this video, we solve GeeksforGeeks Problem of the Day – *Find the Peak Element in a 2D Matrix* using *Binary Search* in Java.

🔹 *Problem Statement*
You are given:
* A 2D matrix mat[][]
* An element is considered a peak if it is greater than or equal to its four neighbors (top, bottom, left, right)
* For boundary cells, missing neighbors are treated as negative infinity
* Multiple peak elements may exist — return any one of them

🔹 *Optimized Approach Used*

*1.* Traverse each row of the matrix
*2.* Apply *Binary Search* on columns to locate a candidate peak
*3.* For the mid element:
* Compare with *top, bottom, left, and right* neighbors
* If it satisfies the peak condition → return its position
*4.* Otherwise:
* Move towards the direction of the *greater neighbor*

📌 *Time Complexity:*
* O(*n log m*)
* n → number of rows
* m → number of columns

📌 *Space Complexity:*
* constant space O(1) (excluding output list)

🔹 *Resources*
* Problem Link: https://www.geeksforgeeks.org/problems/find-the-peak-element-in-a-2d-matrix/1
* Code Link: https://github.com/sibasundarj8/java-DSA/blob/main/BinarySearch/Searching_Find_the_Peak_Element_in_a_2D_Matrix.java
👉 This problem is a classic application of binary search in 2D matrices and is frequently asked in interviews.

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#2dmatrix #binarysearch #gfgdailyproblem #javadsa #dsainjava
#matrixproblems #interviewpreparation #codinginterview
#competitiveprogramming #dailydsapractice #java #gfgpractice

Видео Find the Peak Element in a 2D Matrix | GFG POTD | Binary Search | Java канала The Optimal Approach
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