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Partial Differentiation | Multivariable Calculus | z=tan(y+ax)+(y–ax)^(3/2), ∂²z/∂x²–a²(∂²z/∂y²) = 0
📘 Calculus & Multivariable Calculus | Partial Differentiation Problem Solution
Lecture: Verification of PDE Relation
📝 Problem Statement:
If
z = tan(y + ax) + (y – ax)^(3/2),
then show that
∂²z/∂x² – a²(∂²z/∂y²) = 0.
🎯 Concepts Used:
✔️ Partial Differentiation of Trigonometric Functions
✔️ Partial Differentiation of Algebraic Powers
✔️ Higher Order Partial Derivatives
✔️ PDE Verification in Multivariable Calculus
✨ This problem demonstrates how to verify a Partial Differential Equation (PDE) by computing second-order derivatives and applying algebraic simplification.
✅ Very useful for Engineering Mathematics, Multivariable Calculus, PDEs, and VTU exam preparation.
💎 Support Us:
Join this channel to support us & access exclusive perks 👇
🔗 https://www.youtube.com/channel/UC_OTtwh8_-q-bA7DoS--syg/join
#Calculus #PartialDifferentiation #MultivariableCalculus #Laplacian #EngineeringMathematics #VTU #PDE #ChainRule #BMATS201 #BMATE201 #BMATC201 #BMATM201 #1BMATS101 #1BMATE101 #1BMATC101 #1BMATM101 #Module1 #Module2
Видео Partial Differentiation | Multivariable Calculus | z=tan(y+ax)+(y–ax)^(3/2), ∂²z/∂x²–a²(∂²z/∂y²) = 0 канала Mathematics Tutor
Lecture: Verification of PDE Relation
📝 Problem Statement:
If
z = tan(y + ax) + (y – ax)^(3/2),
then show that
∂²z/∂x² – a²(∂²z/∂y²) = 0.
🎯 Concepts Used:
✔️ Partial Differentiation of Trigonometric Functions
✔️ Partial Differentiation of Algebraic Powers
✔️ Higher Order Partial Derivatives
✔️ PDE Verification in Multivariable Calculus
✨ This problem demonstrates how to verify a Partial Differential Equation (PDE) by computing second-order derivatives and applying algebraic simplification.
✅ Very useful for Engineering Mathematics, Multivariable Calculus, PDEs, and VTU exam preparation.
💎 Support Us:
Join this channel to support us & access exclusive perks 👇
🔗 https://www.youtube.com/channel/UC_OTtwh8_-q-bA7DoS--syg/join
#Calculus #PartialDifferentiation #MultivariableCalculus #Laplacian #EngineeringMathematics #VTU #PDE #ChainRule #BMATS201 #BMATE201 #BMATC201 #BMATM201 #1BMATS101 #1BMATE101 #1BMATC101 #1BMATM101 #Module1 #Module2
Видео Partial Differentiation | Multivariable Calculus | z=tan(y+ax)+(y–ax)^(3/2), ∂²z/∂x²–a²(∂²z/∂y²) = 0 канала Mathematics Tutor
Partial differentiation engineering mathematics Partial differentiation engineering mathematics 1 Partial differentiation vtu Partial Differentiation Partial differentiation engineering mathematics 1 vtu Bmate101 module 2 Bmats101 module 2 partial derivatives engineering mathematics 1 Partial derivatives engineering mathematics partial differentiation engineering mathematics Partial differentiation bsc 1st year multivariable calculus partial derivatives
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26 ноября 2023 г. 17:25:50
00:09:02
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