Leap Year Check – Detailed Version #Python #HackerRank #LeapYear

In this video, we solve a classic programming challenge: determining whether a given year is a leap year. A leap year has an extra day (February 29) that corrects our calendar to match the Earth's orbit around the Sun. This problem is based on the Gregorian calendar rules for leap years, which use three conditions:

A year is a leap year if it is divisible by 4.

However, if the year is divisible by 100, it is not a leap year, unless...

The year is also divisible by 400, in which case it is a leap year.

In our detailed solution, we break down these conditions using Python’s conditional statements and the modulo operator (%), which helps us check divisibility. We explore the concepts of arithmetic operations, boolean logic, and control flow in Python. This explanation is ideal for beginners or anyone looking to reinforce their understanding of these fundamental topics.

Key Topics Covered:

Modulo Operator: Used to determine if one number is evenly divisible by another.

Conditional Statements: The backbone of decision-making in Python.

Boolean Logic: Combining conditions to make clear, logical decisions.

Gregorian Calendar Rules: Understanding why some years are leap years and others are not.

Copy and paste the code below into your Jupyter Notebook to practice the detailed solution!

Code for Detailed Version (Copy-Paste in Jupyter Notebook):

def is_leap(year):
"""
Determine if the provided year is a leap year.

A leap year is defined by the following rules:
1. The year must be evenly divisible by 4;
2. If the year is evenly divisible by 100, it is NOT a leap year,
unless the year is also evenly divisible by 400.

Parameters:
year (int): The year to test.

Returns:
bool: True if the year is a leap year, False otherwise.
"""
# First check: if the year is divisible by 4, it might be a leap year.
if year % 4 == 0:
# Second check: if the year is divisible by 100, it might not be a leap year.
if year % 100 == 0:
# Third check: if the year is divisible by 400, it is a leap year.
if year % 400 == 0:
return True
else:
return False
else:
return True
else:
return False

if __name__ == '__main__':
# Read the input year from STDIN
year = int(input().strip())
# Print the result of the is_leap function (True for leap year, False otherwise)
print(is_leap(year))

Видео Leap Year Check – Detailed Version #Python #HackerRank #LeapYear канала CodeVisium